If you've stared at a binary tree problem, written dfs(root.left) and dfs(root.right) without really knowing why it works, this one's for you.
If you've stared at a binary tree problem, written dfs(root.left) and dfs(root.right) without really...

If you've stared at a binary tree problem, written dfs(root.left) and dfs(root.right) without really knowing why it works, this one's for you.
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